2n^2-n-4=2

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Solution for 2n^2-n-4=2 equation:


Simplifying
2n2 + -1n + -4 = 2

Reorder the terms:
-4 + -1n + 2n2 = 2

Solving
-4 + -1n + 2n2 = 2

Solving for variable 'n'.

Reorder the terms:
-4 + -2 + -1n + 2n2 = 2 + -2

Combine like terms: -4 + -2 = -6
-6 + -1n + 2n2 = 2 + -2

Combine like terms: 2 + -2 = 0
-6 + -1n + 2n2 = 0

Factor a trinomial.
(-3 + -2n)(2 + -1n) = 0

Subproblem 1

Set the factor '(-3 + -2n)' equal to zero and attempt to solve: Simplifying -3 + -2n = 0 Solving -3 + -2n = 0 Move all terms containing n to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -2n = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -2n = 0 + 3 -2n = 0 + 3 Combine like terms: 0 + 3 = 3 -2n = 3 Divide each side by '-2'. n = -1.5 Simplifying n = -1.5

Subproblem 2

Set the factor '(2 + -1n)' equal to zero and attempt to solve: Simplifying 2 + -1n = 0 Solving 2 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1n = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1n = 0 + -2 -1n = 0 + -2 Combine like terms: 0 + -2 = -2 -1n = -2 Divide each side by '-1'. n = 2 Simplifying n = 2

Solution

n = {-1.5, 2}

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